3.1274 \(\int \frac {1}{x^{11} (a+b x^5)} \, dx\)

Optimal. Leaf size=49 \[ -\frac {b^2 \log \left (a+b x^5\right )}{5 a^3}+\frac {b^2 \log (x)}{a^3}+\frac {b}{5 a^2 x^5}-\frac {1}{10 a x^{10}} \]

[Out]

-1/10/a/x^10+1/5*b/a^2/x^5+b^2*ln(x)/a^3-1/5*b^2*ln(b*x^5+a)/a^3

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Rubi [A]  time = 0.03, antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {266, 44} \[ -\frac {b^2 \log \left (a+b x^5\right )}{5 a^3}+\frac {b^2 \log (x)}{a^3}+\frac {b}{5 a^2 x^5}-\frac {1}{10 a x^{10}} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^11*(a + b*x^5)),x]

[Out]

-1/(10*a*x^10) + b/(5*a^2*x^5) + (b^2*Log[x])/a^3 - (b^2*Log[a + b*x^5])/(5*a^3)

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {1}{x^{11} \left (a+b x^5\right )} \, dx &=\frac {1}{5} \operatorname {Subst}\left (\int \frac {1}{x^3 (a+b x)} \, dx,x,x^5\right )\\ &=\frac {1}{5} \operatorname {Subst}\left (\int \left (\frac {1}{a x^3}-\frac {b}{a^2 x^2}+\frac {b^2}{a^3 x}-\frac {b^3}{a^3 (a+b x)}\right ) \, dx,x,x^5\right )\\ &=-\frac {1}{10 a x^{10}}+\frac {b}{5 a^2 x^5}+\frac {b^2 \log (x)}{a^3}-\frac {b^2 \log \left (a+b x^5\right )}{5 a^3}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 49, normalized size = 1.00 \[ -\frac {b^2 \log \left (a+b x^5\right )}{5 a^3}+\frac {b^2 \log (x)}{a^3}+\frac {b}{5 a^2 x^5}-\frac {1}{10 a x^{10}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/(x^11*(a + b*x^5)),x]

[Out]

-1/10*1/(a*x^10) + b/(5*a^2*x^5) + (b^2*Log[x])/a^3 - (b^2*Log[a + b*x^5])/(5*a^3)

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fricas [A]  time = 0.80, size = 45, normalized size = 0.92 \[ -\frac {2 \, b^{2} x^{10} \log \left (b x^{5} + a\right ) - 10 \, b^{2} x^{10} \log \relax (x) - 2 \, a b x^{5} + a^{2}}{10 \, a^{3} x^{10}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^11/(b*x^5+a),x, algorithm="fricas")

[Out]

-1/10*(2*b^2*x^10*log(b*x^5 + a) - 10*b^2*x^10*log(x) - 2*a*b*x^5 + a^2)/(a^3*x^10)

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giac [A]  time = 0.17, size = 55, normalized size = 1.12 \[ -\frac {b^{2} \log \left ({\left | b x^{5} + a \right |}\right )}{5 \, a^{3}} + \frac {b^{2} \log \left ({\left | x \right |}\right )}{a^{3}} - \frac {3 \, b^{2} x^{10} - 2 \, a b x^{5} + a^{2}}{10 \, a^{3} x^{10}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^11/(b*x^5+a),x, algorithm="giac")

[Out]

-1/5*b^2*log(abs(b*x^5 + a))/a^3 + b^2*log(abs(x))/a^3 - 1/10*(3*b^2*x^10 - 2*a*b*x^5 + a^2)/(a^3*x^10)

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maple [A]  time = 0.01, size = 44, normalized size = 0.90 \[ \frac {b^{2} \ln \relax (x )}{a^{3}}-\frac {b^{2} \ln \left (b \,x^{5}+a \right )}{5 a^{3}}+\frac {b}{5 a^{2} x^{5}}-\frac {1}{10 a \,x^{10}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^11/(b*x^5+a),x)

[Out]

-1/10/a/x^10+1/5*b/a^2/x^5+b^2*ln(x)/a^3-1/5*b^2*ln(b*x^5+a)/a^3

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maxima [A]  time = 1.15, size = 47, normalized size = 0.96 \[ -\frac {b^{2} \log \left (b x^{5} + a\right )}{5 \, a^{3}} + \frac {b^{2} \log \left (x^{5}\right )}{5 \, a^{3}} + \frac {2 \, b x^{5} - a}{10 \, a^{2} x^{10}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^11/(b*x^5+a),x, algorithm="maxima")

[Out]

-1/5*b^2*log(b*x^5 + a)/a^3 + 1/5*b^2*log(x^5)/a^3 + 1/10*(2*b*x^5 - a)/(a^2*x^10)

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mupad [B]  time = 0.09, size = 46, normalized size = 0.94 \[ \frac {b^2\,\ln \relax (x)}{a^3}-\frac {b^2\,\ln \left (b\,x^5+a\right )}{5\,a^3}-\frac {\frac {1}{10\,a}-\frac {b\,x^5}{5\,a^2}}{x^{10}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^11*(a + b*x^5)),x)

[Out]

(b^2*log(x))/a^3 - (b^2*log(a + b*x^5))/(5*a^3) - (1/(10*a) - (b*x^5)/(5*a^2))/x^10

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sympy [A]  time = 1.26, size = 42, normalized size = 0.86 \[ \frac {- a + 2 b x^{5}}{10 a^{2} x^{10}} + \frac {b^{2} \log {\relax (x )}}{a^{3}} - \frac {b^{2} \log {\left (\frac {a}{b} + x^{5} \right )}}{5 a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**11/(b*x**5+a),x)

[Out]

(-a + 2*b*x**5)/(10*a**2*x**10) + b**2*log(x)/a**3 - b**2*log(a/b + x**5)/(5*a**3)

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